document.write( "Question 889581: Carlo invested a total of $50,000 in two banks for a year. One investment has an interest rate of 10% per year and the other at 8%. How much should be invested at 8% so that the interest from this investment is twice as big?
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Algebra.Com's Answer #538260 by mananth(16946)\"\" \"About 
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let investment at 8% be x
\n" ); document.write( "investment at 10 % = 50000-x\r
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\n" ); document.write( "\n" ); document.write( "Interest from 8% = 8%x\r
\n" ); document.write( "\n" ); document.write( "Interest from 10% = 10%(50000-x)\r
\n" ); document.write( "\n" ); document.write( "8%x=2*10%(50000-x)\r
\n" ); document.write( "\n" ); document.write( "8x=1000000-20x\r
\n" ); document.write( "\n" ); document.write( "28x=500000\r
\n" ); document.write( "\n" ); document.write( "35,714.30 investment at8%
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