document.write( "Question 889507: You invested $8000 between two accounts paying 4% and 9% annual interest respectively. If the total interest earned for the year was $570, how much was invested at each rate?
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Algebra.Com's Answer #538259 by mananth(16946)\"\" \"About 
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Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 9.00% per annum ------------ Amount invested = y
\n" ); document.write( " 8000
\n" ); document.write( "Interest----- 570.00
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\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 9.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 8000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 9.00% y= 570
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 9 y= 57000.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -32000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 5 y= 25000
\n" ); document.write( "divide by 5
\n" ); document.write( " y = 5000
\n" ); document.write( "Part I 4.00% $ 3000
\n" ); document.write( "Part II 9.00% $ 5000
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\n" ); document.write( "CHECK
\n" ); document.write( "3000 --------- 4.00% ------- 120.00
\n" ); document.write( "5000 ------------- 9.00% ------- 450.00
\n" ); document.write( "Total -------------------- 570.00
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\n" ); document.write( "m.ananth@hotmail.ca
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