document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889557>Question 889557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle is inscribed in a square with vertices(-9,-3),(-1,-3),(-9,5) and (-1,5). <BR>\n" );
document.write( "A)find the coordinates of the center of the circle<BR>\n" );
document.write( "B)find the area of the circle<BR>\n" );
document.write( "C) find the radius of a circle circumscribed about the square </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538252 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538252\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> More than one way to do this.  Look for the midpoint of any pair of opposite corners.  Use distance formula to find half the length of a diagonal.\r<BR>\n" );
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document.write( "A pair of opposite corners is (-1,-3) and (-9,5).\r<BR>\n" );
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document.write( "Center point should be at <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28-1-9%29%2F2=-4 ALIGN=MIDDLE  ALT=\"x=%28-1-9%29%2F2=-4\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28-3%2B5%29%2F2=1 ALIGN=MIDDLE  ALT=\"y=%28-3%2B5%29%2F2=1\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Diagonal length, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%28-1-%28-9%29%29%5E2%2B%28-3-5%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%28-1-%28-9%29%29%5E2%2B%28-3-5%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%288%29%5E2%2B%28-8%29%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%288%29%5E2%2B%28-8%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28128%29 ALIGN=MIDDLE  ALT=\"sqrt%28128%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2864%2A2%29 ALIGN=MIDDLE  ALT=\"sqrt%2864%2A2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"8%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "HALF of that is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%284%2Asqrt%282%29%29 ALIGN=MIDDLE  ALT=\"highlight_green%284%2Asqrt%282%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  This is also the size of the radius of the circle.\r<BR>\n" );
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document.write( "Equation for the circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28%28x%2B4%29%5E2%2B%28x-1%29%5E2=%284sqrt%282%29%29%5E2%29 ALIGN=MIDDLE  ALT=\"highlight%28%28x%2B4%29%5E2%2B%28x-1%29%5E2=%284sqrt%282%29%29%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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