document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74907>Question 74907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 22and 1fourth multiply 4and 1third = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53825 by </B><A HREF=/tutors/aboutme.mpl?userid=cathieb1225><B>cathieb1225(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cathieb1225><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53825\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 22and 1fourth multiply 4and 1third =<BR>\n" );
document.write( "(22 1/4)(4 1/3)<BR>\n" );
document.write( "Convert both into improper fractions. You do this by multiplying the number with the denominator and adding the numerator. Thus, 22 1/4=89/4 and 4 1/3=13/3<BR>\n" );
document.write( "(89/4)(13/3)=1157/12=96 5/12\r<BR>\n" );
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