document.write( "Question 889518: Homer and Mike were replacing the boards on Mike's old deck. Mike can do the job alone in 1 hour less time than Homer. They worked together for 3 hours until Homer had to go home. Mike finished the job working by himself in an additional 3 hours. How long would it have taken Homer to fix the deck himself?\r
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document.write( "It will take Homer appropriately ___ hours ____ minutes to fix the deck by himself.\r
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document.write( "(Round to the nearest minute as needed). \n" );
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Algebra.Com's Answer #538219 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Homer and Mike were replacing the boards on Mike's old deck. Mike can do the job alone in 1 hour less time than Homer. They worked together for 3 hours until Homer had to go home. Mike finished the job working by himself in an additional 3 hours. How long would it have taken Homer to fix the deck himself? \n" ); document.write( "*** \n" ); document.write( "let x=hours Homer can do the job alone \n" ); document.write( "1/x=his work rate \n" ); document.write( "x-1=hours Mike can do the job alone \n" ); document.write( "1/(x-1)=his work rate \n" ); document.write( "sum of indv. work rates=work rate working together \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "3 hrs working together+mike working 3 hrs by himself=100% of the job \n" ); document.write( "3(2x-1)/x(x-1)+3(x-1)=1 \n" ); document.write( "lcd: x(x-1) \n" ); document.write( "6x-3+3x=x(x-1) \n" ); document.write( "6x-3+3x=x^2-x \n" ); document.write( "x^2-10x+3=0 \n" ); document.write( "solve for x by quadratic formula: \n" ); document.write( " \n" ); document.write( "a=1, b=-10, c=3 \n" ); document.write( "ans: x≈0.31 (reject) \n" ); document.write( "or \n" ); document.write( "x≈9.7 \n" ); document.write( "It will take Homer approximately 9 hours 42 minutes to fix the deck by himself. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |