document.write( "Question 889518: Homer and Mike were replacing the boards on Mike's old deck. Mike can do the job alone in 1 hour less time than Homer. They worked together for 3 hours until Homer had to go home. Mike finished the job working by himself in an additional 3 hours. How long would it have taken Homer to fix the deck himself?\r
\n" ); document.write( "\n" ); document.write( "It will take Homer appropriately ___ hours ____ minutes to fix the deck by himself.\r
\n" ); document.write( "\n" ); document.write( "(Round to the nearest minute as needed).
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Algebra.Com's Answer #538218 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Uniform Rates Situation for Doing A Job, RT=J rate time job
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\n" ); document.write( "Individual Rates:
\n" ); document.write( "Homer, 1/x
\n" ); document.write( "Mike, 1/(x-1)
\n" ); document.write( "x=time for Homer alone to do the one job.\r
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\n" ); document.write( "\n" ); document.write( "They worked together for 3 hours\r
\n" ); document.write( "\n" ); document.write( "\"%281%2Fx%29%2A3%2B%281%2F%28x-1%29%29%2A3\", the amount of job done.\r
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\n" ); document.write( "\n" ); document.write( "Mike finished the job working by himself in an additional 3 hours.\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F%28x-1%29%29%2A3\",Finishing the undone part of the job.\r
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\n" ); document.write( "\n" ); document.write( "Both of those parts make a sum of 1 whole job.
\n" ); document.write( "\"highlight%28%281%2Fx%29%2A3%2B%281%2F%28x-1%29%29%2A3%2B%281%2F%28x-1%29%29%2A3=1%29\";
\n" ); document.write( "Understanding how this equation is developed is most of the solution. The solving of the equation is just arithmetic with variable x in it. Solve for x.
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