document.write( "Question 889520: 2 cos^2 sigma sign + sin sigma symbol-2=0\r
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Algebra.Com's Answer #538211 by lwsshak3(11628)\"\" \"About 
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2 cos^2 sigma sign + sin sigma symbol-2=0
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\n" ); document.write( "use x for sigma:
\n" ); document.write( "solve for x
\n" ); document.write( "2cos^x+six-2=0
\n" ); document.write( "2(1-sin^2x)+sinx-2=0
\n" ); document.write( "2-2sin^2x+sinx-2=0
\n" ); document.write( "-2sin^2x+sinx=0
\n" ); document.write( "sinx(-2sinx+1)=0
\n" ); document.write( "..
\n" ); document.write( "sinx=0
\n" ); document.write( "x=0
\n" ); document.write( "or
\n" ); document.write( "-2sinx+1=0
\n" ); document.write( "sinx=1/2
\n" ); document.write( "x=π/4, 3π/4
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