document.write( "Question 889520: 2 cos^2 sigma sign + sin sigma symbol-2=0\r
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document.write( "interval [0,2π) \n" );
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Algebra.Com's Answer #538211 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 2 cos^2 sigma sign + sin sigma symbol-2=0 \n" ); document.write( "interval [0,2π) \n" ); document.write( "*** \n" ); document.write( "use x for sigma: \n" ); document.write( "solve for x \n" ); document.write( "2cos^x+six-2=0 \n" ); document.write( "2(1-sin^2x)+sinx-2=0 \n" ); document.write( "2-2sin^2x+sinx-2=0 \n" ); document.write( "-2sin^2x+sinx=0 \n" ); document.write( "sinx(-2sinx+1)=0 \n" ); document.write( ".. \n" ); document.write( "sinx=0 \n" ); document.write( "x=0 \n" ); document.write( "or \n" ); document.write( "-2sinx+1=0 \n" ); document.write( "sinx=1/2 \n" ); document.write( "x=π/4, 3π/4 \n" ); document.write( " |