document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889486>Question 889486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not sure how to solve this algebraically.\r<BR>\n" );
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document.write( "y=1/3x+1<BR>\n" );
document.write( "y=3/x+3\r<BR>\n" );
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document.write( "Please help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538189 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> begin by setting the two equations = to each other and solving for x<BR>\n" );
document.write( "1/(3x) +1 = 3/x +3<BR>\n" );
document.write( "subtract 1 from both sides of =<BR>\n" );
document.write( "1/(3x) = 3/x +2<BR>\n" );
document.write( "multiply both sides of = by 3x<BR>\n" );
document.write( "1 = 9 +6x<BR>\n" );
document.write( "subtract 9 from both sides of = <BR>\n" );
document.write( "6x = -8<BR>\n" );
document.write( "x = -4/3<BR>\n" );
document.write( "substitute for x in first equation, then<BR>\n" );
document.write( "y = 3/4<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "x = -4/3 and y = 3/4\r<BR>\n" );
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document.write( " </SPAN>\n" );
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