document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889395>Question 889395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mike and Dan bought a foot long sub sandwich and decided that it would be fair for Dan to have a third more of the sandwich than Mike. Ho… </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538134 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mike and Dan bought a foot long sub sandwich and decided that it would be fair for Dan to have a third more of the sandwich than Mike. <BR>\n" );
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document.write( "Let Mike have \"x\":<BR>\n" );
document.write( "Then Dan must have \"(4/3)x\"<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + (4/3)x = 12 inches<BR>\n" );
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document.write( "(7/3)x = 12<BR>\n" );
document.write( "x = (3/7)12 = 36/7 = 5 1/7 inches (Mike's share)<BR>\n" );
document.write( "(4/3)x = (4/3)(36/7) = 48/7 == 6 6/7 inches (Dan's share)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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