document.write( "Question 889306: The age of A is twice that of B.8 years hence their ages will be in the ratio 5:3.Find their present ages?
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Algebra.Com's Answer #538130 by ankor@dixie-net.com(22740)\"\" \"About 
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The age of A is twice that of B.
\n" ); document.write( "a = 2b
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\n" ); document.write( "8 years hence their ages will be in the ratio 5:3.
\n" ); document.write( "\"%28%28a%2B8%29%29%2F%28%28b%2B8%29%29\" = \"5%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3(a+8) = 5(b+8)
\n" ); document.write( "3a + 24 = 5b + 40
\n" ); document.write( "3a = 5b + 40 - 24
\n" ); document.write( "3a = 5b + 16
\n" ); document.write( "replace a with 2b, (from the 1st statement)
\n" ); document.write( "3(2b) = 5b + 16
\n" ); document.write( "6b - 5b = 16
\n" ); document.write( "b = 16 is B's age
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\n" ); document.write( "I'll let you find A's age, check your solution in the 2nd statement
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