document.write( "Question 74896: Can anyone help me with this?\r
\n" ); document.write( "\n" ); document.write( "My problem is how to rationalize the denominator:\r
\n" ); document.write( "\n" ); document.write( "2/ sqrt[6] - sqrt[5]
\n" ); document.write( "

Algebra.Com's Answer #53812 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
SEEMS LIKE I'VE DONE THIS ONE BEFORE.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2%2F%28sqrt%286%29-sqrt%285%29%29\" First, multiply both numerator and denominator by \"%28sqrt%286%29%2Bsqrt%285%29%29\" we can do this because \"%28sqrt%286%29%2Bsqrt%285%29%29%2F%28sqrt%286%29%2Bsqrt%285%29%29\" equals 1 and we want to do this to get rid of the radicals in the denominator.\r
\n" ); document.write( "\n" ); document.write( " and this equals\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28%282%29%28sqrt%286%29%2Bsqrt%285%29%29%29%2F%286-5%29\" and this reduces to:\r
\n" ); document.write( "\n" ); document.write( "\"2%28sqrt%286%29%2Bsqrt%285%29%29\" ------------ans\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );