document.write( "Question 889324: the perimeter of a rectangle is 50 centimeters the length is 1 cm more than twice the width. what is the width
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Algebra.Com's Answer #538074 by rosnixnath(1)\"\" \"About 
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P = 2 x L + 2 x W\r
\n" ); document.write( "\n" ); document.write( "P = 50 cm\r
\n" ); document.write( "\n" ); document.write( "L = 2W + 1\r
\n" ); document.write( "\n" ); document.write( "50 = 2 x (2W + 1 ) + 2W\r
\n" ); document.write( "\n" ); document.write( "48 = 6W\r
\n" ); document.write( "\n" ); document.write( "W = 8 cm
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