document.write( "Question 889284: 1)find the smallest square number which is divisible by 6,12 and 15
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Algebra.Com's Answer #538035 by Edwin McCravy(20060)\"\" \"About 
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1)find the smallest square number which is divisible by 6,12 and 15
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document.write( "Break the numbers into their prime factorization:\r\n" );
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document.write( " 6 = 2×3\r\n" );
document.write( "12 = 2×2×3\r\n" );
document.write( "15 = 3×5\r\n" );
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document.write( "A square number must have an even number of each prime factor.\r\n" );
document.write( "So it must have two factors each of 2, 3, and 5.  So the smallest\r\n" );
document.write( "square number is 2×2×3×3×5×5 = 900

\n" ); document.write( "2)the opposite angles of a parallelogram are 2x+10 decree and 3x-20 degrees. Find all the angles of parallelogram.
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document.write( "The opposite angles of a parallelogram are equal.  Set them equal and solve:\r\n" );
document.write( "2x+10 = 3x-20\r\n" );
document.write( "   30 = x\r\n" );
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document.write( "So one pair of equal opposite angles are 30° each. The other pair of\r\n" );
document.write( "opposite angles are supplementary to them, so they are 180°-30° or 150° each.
3)the 3 angles of a quadrilateral are in the ratio of 2:3:5 and the fourth angle is 60 decree. Find the measure of the first three angles.
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document.write( "Since the four angles of any quadrilateral have sum 360°, the three angles\r\n" );
document.write( "in the ratio 2:3:5 have sum 360°-60° or 300°.  Let their constant of \r\n" );
document.write( "proportionality be k, then the three angles are 2k, 3k, and 5k\r\n" );
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document.write( "2k+3k+5k = 300°\r\n" );
document.write( "     10k = 300°\r\n" );
document.write( "       k = 30°\r\n" );
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document.write( "So the other three angles are \r\n" );
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document.write( "2k = 2(30°) = 60°  \r\n" );
document.write( "3k = 3(30°) = 90°\r\n" );
document.write( "5k = 5(30°) = 150°\r\n" );
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document.write( "Edwin

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