document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889285>Question 889285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the product of 3 consecutive integers is 120,then the sum of the integers is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538032 by </B><A HREF=/tutors/aboutme.mpl?userid=dkppathak><B>dkppathak(439)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dkppathak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=dkppathak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538032\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the product of 3 consecutive integers is 120,then the sum of the integers <BR>\n" );
document.write( "solution <BR>\n" );
document.write( "let numbers are <BR>\n" );
document.write( "X,(X+1) ,(X+2)<BR>\n" );
document.write( "then as per conditions <BR>\n" );
document.write( "X(X+1)(X+2)=120 to find X+(X+1)+(X+2)=? <BR>\n" );
document.write( "X(X+1)(X+2)=4x5x6<BR>\n" );
document.write( "than x=4 or x+1=4 or x+2=6<BR>\n" );
document.write( "in each case we will find that <BR>\n" );
document.write( "X=4<BR>\n" );
document.write( "therefor three consecutive number are X,(X+1) ,(X+2) or 3,4,5<BR>\n" );
document.write( "therefor sum will be 4+5+6 =15<BR>\n" );
document.write( "answer 15 </SPAN>\n" );
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