document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889242>Question 889242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove:\r<BR>\n" );
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document.write( "1-cot^2x/1+cot^2x=2cos^2-1\r<BR>\n" );
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document.write( "I tried this: <BR>\n" );
document.write( "LHS<BR>\n" );
document.write( "=1-(cos^2x/sin^2x)/csc^2x<BR>\n" );
document.write( "=(sin^2x-cos^2x/sin^2x)/(1/sin^x)<BR>\n" );
document.write( "=sin^2x-cos^2x/sin^2x(sin^2x/1)<BR>\n" );
document.write( "sin^^2x-cos^2x\r<BR>\n" );
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document.write( "RHS<BR>\n" );
document.write( "2cos^2-1=cos(2x)\r<BR>\n" );
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document.write( "So, after this, I don't know what to do. Thank you!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #538005 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=538005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sin^2(x) - cos^2(x) = cos(2x) </SPAN>\n" );
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