document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889189>Question 889189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^3 + 100\r<BR>\n" );
document.write( "\n" );
document.write( "I tried to factor out the answer, but since 100 is not a cube, I ended up getting huge decimals and imaginary numbers. If anyone can help me with this, it would be great. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537974 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try looking for possible rational roots and check them until you have all of degree three taken care of.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1,2,5,10,20,25,50.  Use synthetic division to check each of those as possible roots.  Review Rational Roots Theorem.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "One root is seen on a graph, but it is probably NOT rational; most likely must be irrational.  None of the \"possible\" roots I listed is any rational root for x^3+100.  Best guess, the value looks like cubed root of 100. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );