document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74829>Question 74829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pamela has 50 feet of fencing tp put around a rectangular dog pen.  Her house is used as one side of the pen. A 2 feet opening is left on another side for a gate. What length and width will provide a maximim area for her dog? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53796 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FOR A RECTANCLE TO ENCLOSE THE MAXIMUM AREA IT SHOULD BE A SQUARE. THUS THREE SIDES OF THE SQUARE HERE WOULD TOTAL 50+2=52 FEET (FENCE + GATE)<BR>\n" );
document.write( "SEEING AS THERE ARE ONLY THREE SIDES, THE HOUSE BEING THE FOURTH SIDE. WE DIVIDE 52 BY 3=17 1/3 FEET PER SIDE (LENGTH & WIDTH).<BR>\n" );
document.write( "17.333*17.333=300.444 SQUARE FEET IS THE MAXIMUM FOR THE AREA ENCLOSED.   </SPAN>\n" );
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