document.write( "Question 889169: What is
\n" ); document.write( "sin(u+v)+sin(u-v)/cos(u+v)+cos(u-v)=tan (u)\r
\n" ); document.write( "\n" ); document.write( "I have tried answering it:
\n" ); document.write( "LHS>>>
\n" ); document.write( "=[sin(u)cos(v)+cos(u)sin(v)]+[sin(u)cos(v)+cos(u)sin(v)]/[cos(u)cos(v)-sin(u)sin(v)]+[cos(u)cos(v)+sin(u)sin(v)]
\n" ); document.write( "=sin(u)cos(v)+sin(u)cos(v)/cos(u)cos(v)+cos(u)cos(v)
\n" ); document.write( "=2sin(u)cos(v)/2cos(u)cos(v)\r
\n" ); document.write( "\n" ); document.write( "and i'm stuck here. I don't know how i'll make it equal to the RHS (tan u).
\n" ); document.write( "Please help me out. Thanks
\n" ); document.write( "

Algebra.Com's Answer #537945 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
It's right there.
\n" ); document.write( "\"%282sin%28u%29cos%28v%29%29%2F%282cos%28u%29cos%28v%29%29\"
\n" ); document.write( "Cancel out the \"2cos%28v%29\" terms from numerator and denominator.
\n" ); document.write( "\"sin%28u%29%2Fcos%28u%29\"
\n" ); document.write( "\"tan%28u%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );