document.write( "Question 889070: Farmer Fred wants to fence in a rectangular pasture that is bordered on one side by a river. He plans to use 7200 feet of fence to enclose the other three sides . What should the dimensions of the pasture be if the enclosed area is to be maximum? \n" ); document.write( "
Algebra.Com's Answer #537926 by Fombitz(32388)\"\" \"About 
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Let the side parallel to the river be X and the other side Y.
\n" ); document.write( "\"X%2BX%2BY=7200\"
\n" ); document.write( "\"2X%2BY=7200\"
\n" ); document.write( "The area would then be,
\n" ); document.write( "\"A=XY\"
\n" ); document.write( "Substitute for Y using the perimeter equation,
\n" ); document.write( "\"Y=7200-2X\"
\n" ); document.write( "\"A=X%287200-2X%29=7200X-2X%5E2\"
\n" ); document.write( "To find the extrema, differentiate with respect to X and set the derivative equal to zero.
\n" ); document.write( "\"dA%2FdX=7200-4X=0\"
\n" ); document.write( "\"X=7200%2F4\"
\n" ); document.write( "\"highlight%28X=1800%29\"
\n" ); document.write( "Then,
\n" ); document.write( "\"Y=7200-3600\"
\n" ); document.write( "\"highlight%28Y=3600%29\"
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