document.write( "Question 889067: The sum of four numbers is 56. First number is twice as second and third number is as half of the second and fourth number is 3 times the sum of 1st and 2nd number. Find the numbers? \n" ); document.write( "
Algebra.Com's Answer #537917 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"A%2BB%2BC%2BD=56\"
\n" ); document.write( "\"A=2B\"
\n" ); document.write( "\"C=%281%2F2%29B\"
\n" ); document.write( "\"D=3%28A%2BB%29=3%282B%2BB%29=3%283B%29=9B\"
\n" ); document.write( "Substituting,
\n" ); document.write( "\"2B%2BB%2B%281%2F2%29B%2B9B=56\"
\n" ); document.write( "\"%2825%2F2%29B=56\"
\n" ); document.write( "\"highlight%28B=112%2F25%29\"
\n" ); document.write( "Then,
\n" ); document.write( "\"A=2%28112%2F25%29\"
\n" ); document.write( "\"highlight%28A=224%2F25%29\"
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\n" ); document.write( "\"C=%281%2F2%29%28112%2F25%29\"
\n" ); document.write( "\"highlight%28C=56%2F25%29\"
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\n" ); document.write( "\"D=3%28224%2F25%2B112%2F25%29\"
\n" ); document.write( "\"D=3%28336%2F25%29\"
\n" ); document.write( "\"highlight%28D=1008%2F25%29\"\r
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