document.write( "Question 889087: A man travels 40km down a river and back in 6 hours. If the speed of river current is 5km/hr, find speed of boat in still water. \n" ); document.write( "
Algebra.Com's Answer #537883 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A man travels 40km down a river and back in 6 hours. If the speed of river current is 5km/hr, find speed of boat in still water. \n" ); document.write( "*** \n" ); document.write( "let x=speed of boat in still water \n" ); document.write( "x+5=speed of boat in down river \n" ); document.write( "x-5=speed of boat in up river \n" ); document.write( "travel time=distance/speed \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( "lcd:(x+5)(x-5) \n" ); document.write( "40(x-5)+40(x+5)=6(x^2-25) \n" ); document.write( "40x-200+40x+200=6x^2-150 \n" ); document.write( "6x^2-80x-150=0 \n" ); document.write( "3x^2-40x-75=0 \n" ); document.write( "(3x+5)(x-15)=0 \n" ); document.write( "x=-5/3 (reject) \n" ); document.write( "or \n" ); document.write( "x=15 \n" ); document.write( "speed of boat in still water=15 mph \n" ); document.write( " \n" ); document.write( " |