document.write( "Question 889065: a job can be done in as many days as there men in the group. if the number of men is reduced by 4, the job will be delayed by 5 days. How many men were there originally in the group? \n" ); document.write( "
Algebra.Com's Answer #537874 by josgarithmetic(39628)\"\" \"About 
You can put this solution on YOUR website!
One job can be done in d days by d men in the group. if the number of men is reduced by 4, the job will be delayed by 5 days. How many men were there originally in the group?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Reducing the number of men to d-4 makes the 1 job require d+5 days.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The d men in d days did one job. The reduced men, more days arrangement was also for one job. The number of jobs is equal.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "RT=J for rate, time, job. We can use r for the one-man work rate.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight_green%28d%2Ar%2Ad=1=%28d-4%29r%28d%2B5%29%29\".
\n" ); document.write( "The factor of r occurs on both sides of the equation, and the only other variable resulting in terms in powers of one and two is d. Solve for d.
\n" ); document.write( "
\n" );