document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889047>Question 889047</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help please.If k is a negative number, then which of the following equations will have two imaginary solution? (a) (x+1)^2=-k (b)2x^2+5k=0 (c)(x-5)^2=k=0 (d) k-3x^2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537860 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+1)^2=-k will have real solutions since k < 0 leads to -k > 0\r<BR>\n" );
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document.write( "So choice A is out.\r<BR>\n" );
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document.write( "2x^2+5k=0\r<BR>\n" );
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document.write( "2x^2=-5k\r<BR>\n" );
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document.write( "will have real solutions since -5k is also positive (same reasoning as A)\r<BR>\n" );
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document.write( "choice B is out\r<BR>\n" );
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document.write( "There's a typo in choice C\r<BR>\n" );
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document.write( "You wrote (x-5)^2=k=0\r<BR>\n" );
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document.write( "k-3x^2=0\r<BR>\n" );
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document.write( "3x^2 = k\r<BR>\n" );
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document.write( "this leads to two imaginary solutions since k < 0 </SPAN>\n" );
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