document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888975>Question 888975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how long would it take to slow down from 80 miles an hour in a quarter mile. \r<BR>\n" );
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document.write( "what is the rate of slow down per foot </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537843 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537843\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how long would it take to slow down from 80 miles an hour in a quarter mile.<BR>\n" );
document.write( "Assuming uniform acceleration:<BR>\n" );
document.write( "s = at^2/2<BR>\n" );
document.write( "v = at<BR>\n" );
document.write( "s = vt/2<BR>\n" );
document.write( "t = 2s/v = 2*(1/4)/80 = 1/160 hour = 22.5 seconds<BR>\n" );
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document.write( "what is the rate of slow down per foot<BR>\n" );
document.write( "1/4 mile = 1320 feet<BR>\n" );
document.write( "80 mi/hr = 80*22/15 ft/sec = 352/3 ft/sec<BR>\n" );
document.write( "Not sure what you mean by \"slow down per foot\"  </SPAN>\n" );
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