document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=889017>Question 889017</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A silversmith needs 40 pounds of a 48% silver alloy to finish a collection of jewelry. How many pounds of 45% silver alloy should he melt with a 60% silver alloy to obtain the alloy he needs. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A silversmith needs 40 pounds of a 48% silver alloy to finish a collection of jewelry. How many pounds of 45% silver alloy should he melt with a 60% silver alloy to obtain the alloy he needs.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "silver + silver = silver<BR>\n" );
document.write( "0.45x + 0.60(40-x) = 0.48*40<BR>\n" );
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document.write( "45x + 60*40 - 60x = 48*40<BR>\n" );
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document.write( "-15x = -12*40<BR>\n" );
document.write( "x = (4/5)40<BR>\n" );
document.write( "x = 32 lbs (amt of 45% slloy needed)<BR>\n" );
document.write( "40-x = 8 lbs (amt of 60% alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );