document.write( "Question 888891: I need help figuring this out. Thank you.\r
\n" ); document.write( "\n" ); document.write( "Solve 2 sin^2 a-5 sin a-3=0 in the interval 0° <= m(a)< 360° \n" ); document.write( "

Algebra.Com's Answer #537793 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"x=sin%28a%29\"$
\n" ); document.write( " $\"2x%5E2-5x-3=0\"$
\n" ); document.write( " $\"%28x-3%29%282x%2B1%29=0\"$
\n" ); document.write( "Two solutions:
\n" ); document.write( " $\"x-3=0\"$
\n" ); document.write( " $\"x=3\"$
\n" ); document.write( " $\"sin%28a%29=3\"$
\n" ); document.write( "Not a valid solution.
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"2x%2B1=0\"$
\n" ); document.write( " $\"2x=-1\"$
\n" ); document.write( " $\"x=-1%2F2\"$
\n" ); document.write( " $\"sin%28a%29=-1%2F2\"$
\n" ); document.write( " $\"a=210\"$ degrees and $\"a=330\"$ degrees \n" ); document.write( "

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