document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888782>Question 888782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the triangle with vertices A(6,-7), B(11,-3) and <BR>\n" );
document.write( "C(2,-2). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537679 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of the triangle with vertices A(6,-7), B(11,-3) and <BR>\n" );
document.write( "C(2,-2).<BR>\n" );
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document.write( "x: 6 11 +2 +6<BR>\n" );
document.write( "y:-7 -3 -2 -7<BR>\n" );
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document.write( "Add the diagonal products starting at the upper left.<BR>\n" );
document.write( "-18 - 22 - 14 = -54<BR>\n" );
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document.write( "Add the diagonal products starting at the lower left.<BR>\n" );
document.write( "-77 - 6 - 12 = -95<BR>\n" );
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document.write( "Area = 1/2 the difference = 41/2<BR>\n" );
document.write( "Area = 20.5 sq units\r<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );