document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888765>Question 888765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a summer reading list with 15 books and you have to read 3. How many different combinations of books can you read? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537667 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537667\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 15*14*13 = 2,730 ways to read 3 books where order matters.\r<BR>\n" );
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document.write( "Since order does not matter, we divide by 3! = 3*2*1 = 6 to get 2,730/6 = 455\r<BR>\n" );
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document.write( "There are <font color=\"red\">455</font> different combinations. </SPAN>\n" );
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