document.write( "Question 888691: Please help me to find x and y : ln 2x + 10 = 2 ln 2 \n" ); document.write( "
Algebra.Com's Answer #537587 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
ln(2x) + 10 = 2ln(2)\r
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\n" ); document.write( "\n" ); document.write( "subtract 10 from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "ln(2x) = 2ln(2) - 10\r
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\n" ); document.write( "\n" ); document.write( "since 2ln(2) is equal to ln(2^2) = ln(4), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "ln(2x) = ln(4) - 10\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "ln(2x) = -8.613705639\r
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\n" ); document.write( "\n" ); document.write( "this is true if and only if e^-8.613705639 = 2x\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 2 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = e^-8.613705639 / 2 which becomes:\r
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\n" ); document.write( "\n" ); document.write( "x = 9.079985952 * 10^-5.\r
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\n" ); document.write( "\n" ); document.write( "that should be your answer.\r
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\n" ); document.write( "\n" ); document.write( "replace x in the original equation with that to see if the equation holds true.\r
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\n" ); document.write( "\n" ); document.write( "original equation is:\r
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\n" ); document.write( "\n" ); document.write( "ln(2x) + 10 = 2ln(2) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "ln(2*9.079985952 * 10^-5) + 10 = 2ln(2) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "1.386294361 = 1.386294361\r
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\n" ); document.write( "\n" ); document.write( "this confirms the solution is correct.\r
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\n" ); document.write( "\n" ); document.write( "i did not see a y in your equation.\r
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