document.write( "Question 888663: 1. A turtle and a rabbit engage in a footrace over a distance of 4.00 km. The rabbit runs 0.500 km
\n" ); document.write( "and then stops for a 90.0-min nap. Upon awakening, he remembers the race and runs twice as
\n" ); document.write( "fast. Finishing the course in a total time of 1.75 h, the rabbit wins the race. (a) Calculate the
\n" ); document.write( "average speed of the rabbit. (b) What was his average speed before he stopped for a nap?
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Algebra.Com's Answer #537568 by richwmiller(17219)\"\" \"About 
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1.75 h=60+45=105 minutes
\n" ); document.write( "105-90=15 minutes running\r
\n" ); document.write( "\n" ); document.write( "4/1.75 =2.2857 kmph average for the 1.75 hours\r
\n" ); document.write( "\n" ); document.write( "per hour
\n" ); document.write( "a+b=.25
\n" ); document.write( "r*a=.5
\n" ); document.write( "2r*b=3.5\r
\n" ); document.write( "\n" ); document.write( "a=0.0555556 hr b, b=0.194444 hr, r=9 kph before his nap.\r
\n" ); document.write( "\n" ); document.write( "per minute
\n" ); document.write( "a+b=15
\n" ); document.write( "r*a=.5
\n" ); document.write( "2r*b=3.5\r
\n" ); document.write( "\n" ); document.write( "a=3.33333 minutes before nap, b=11.6667 minutes after nap, r=0.15 km per minute before his nap\r
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