document.write( "Question 888659: find two numbers such that one number is 5 greater than the other number. If the sum of their squares is 5 times the square of half the smaller number, what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #537559 by mananth(16946)\"\" \"About 
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let one number be x
\n" ); document.write( "the other will be x+5\r
\n" ); document.write( "\n" ); document.write( "x^2+(x+5)^2 = 5(x/2)^2\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2+10x+25=5x^2/4\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 4\r
\n" ); document.write( "\n" ); document.write( "4x^2+4x^2+40x+100 = 5x^2\r
\n" ); document.write( "\n" ); document.write( "3x^2+40x+100=0\r
\n" ); document.write( "\n" ); document.write( "3x^2+30x+10x+100=0\r
\n" ); document.write( "\n" ); document.write( "3x(x+10)+10(x+10)=0\r
\n" ); document.write( "\n" ); document.write( "(x+10)(3x+10)=0\r
\n" ); document.write( "\n" ); document.write( "x=-10 OR -10/3\r
\n" ); document.write( "\n" ); document.write( "if x= -10
\n" ); document.write( "then x+5 =-5\r
\n" ); document.write( "\n" ); document.write( "The numbers are -10,-5\r
\n" ); document.write( "\n" ); document.write( "-10/3 , 5/3\r
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