document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=74783>Question 74783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of the second angle of a triangle is twice as great as that of the first angle.  If the measure of the thrid angle is 20 degrees greater than that of the second angle, what is measure of the third angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #53755 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=53755\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Let x=the measure of the first angle<BR>\n" );
document.write( "Then 2x=the measure of the second angle<BR>\n" );
document.write( "And (2x+20)=the measure of the third angle\r<BR>\n" );
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document.write( "Now we know that all three angles must add up to 180 degrees.  So:\r<BR>\n" );
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document.write( "x+2x+(2x+20)=180  get rid of parens\r<BR>\n" );
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document.write( "x+2x+2x+20=180  subtract 20 from both sides<BR>\n" );
document.write( "x+2x+2x+20-20=180-20  collect like terms\r<BR>\n" );
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document.write( "5x=160   divide both sides by 5<BR>\n" );
document.write( "x=32 degrees--------------------first angle\r<BR>\n" );
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document.write( "2x+20=2(32)+20=64+20= 84 degrees third angle-----------------------ans\r<BR>\n" );
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document.write( "2x=2(32)=64 degrees ------------second angle\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "84+64+32=180<BR>\n" );
document.write( "180=180\r<BR>\n" );
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document.write( "also 64 equals two times 32 and 84 equals 2 times 32 +20\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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