document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888655>Question 888655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to Chebyshev's theorem, what proportion of a distribution will be within k = 4 standard deviations of the mean?  Show all work as to how to find this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537546 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By Chebyshev's theorem, at most 1/4^2 = 1/16 of the population is greater than 4 standard deviations.\r<BR>\n" );
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document.write( "Therefore at least 15/16 of the population is within 4 standard deviations. </SPAN>\n" );
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