document.write( "Question 888631: On a standard measure of hearing ability, the mean is 300 and the standard deviation is 20. Give the raw scores for persons whose Z scores for persons who score 340, 310, and 260. Give the raw scores for persons whose Z scores on this test are 2.4, 1.5, and -4.5. \n" ); document.write( "
Algebra.Com's Answer #537539 by Okamiden(22)![]() ![]() ![]() You can put this solution on YOUR website! Z score for someone with 340 : \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "It is simply how many units of \"20\" the persion deviates from the mean \"300\". The person who scores 340 deviates two standard deviations of \"20\" from the mean. \n" ); document.write( "Answer: 2. \n" ); document.write( "If we have 310, the same logic applies: \n" ); document.write( "260: \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "With Z-scores, it's how many standard deviations away from the mean you are. \n" ); document.write( ". \n" ); document.write( "Z-score 2.4: \n" ); document.write( "Take the mean and add 2.4 times the standard deviation. \n" ); document.write( "300+2.4*20 = 348. \n" ); document.write( ". \n" ); document.write( "For the two others: \n" ); document.write( "300+1.5*20 = 330 \n" ); document.write( "300-4.5*20 = 210 \n" ); document.write( ". \n" ); document.write( "Hope that helps. :)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |