document.write( "Question 888572: over a specified distance speed varies inversely with the time. If a odge viper on a test track goes a certain distance in ne-half minute at 160 mpg, what speed is needed to go the same distance in three-fourths minute? \n" ); document.write( "

Algebra.Com's Answer #537512 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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): over a specified distance speed varies inversely with the time.
\n" ); document.write( " If a dodge viper on a test track goes a certain distance in one-half minute at 160 mph, what speed is needed to go the same distance in three-fourths minute?
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\n" ); document.write( "Find the distance traveled in 30 sec (in ft)
\n" ); document.write( " $\"%28160%2A5280%29%2F3600\"$ * 30 = 7040 ft
\n" ); document.write( ":
\n" ); document.write( "Let s = speed required to go 7040 ft in 45 sec
\n" ); document.write( "45s = 7040
\n" ); document.write( "s = 7040/45
\n" ); document.write( "s = 156.44 ft/sec
\n" ); document.write( ":
\n" ); document.write( "In mph: $\"%283600%2A156.44%29%2F5280\"$ = 106 $\"2%2F3\"$ mph
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\n" ); document.write( "Actually we did not have to got thru all this, use an inverse ratio relationship
\n" ); document.write( " $\"s%2F160\"$ = $\"30%2F45\"$
\n" ); document.write( "Cross multiply and see what you get. \n" ); document.write( "

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