document.write( "Question 74813This question is from textbook College Algebra
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document.write( ": Two ships leave port at the same time. One sails south at 15 mi/h and the other sails east at 20 mi/h. Find the function that models the distance (D) between the ships in terms of the time [(t) in hours] elapsed since their departure. \n" );
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Algebra.Com's Answer #53751 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! This is a Pythagorean theorem problem. The two ships are at the vertex of a right angle. \n" ); document.write( ". \n" ); document.write( "One ship sails east and the distance it is from the starting point is 20*t where t is the time \n" ); document.write( "that it has been underway. \n" ); document.write( ". \n" ); document.write( "The other ship sails south which is at an angle of 90 degrees to the path of the ship that \n" ); document.write( "is going east. The distance that it is from the starting point is 15*t where t is also the \n" ); document.write( "time that it has been underway. \n" ); document.write( ". \n" ); document.write( "Both of these paths are the legs of a right triangle. The distance between the ships is \n" ); document.write( "the hypotenuse of the triangle. \n" ); document.write( ". \n" ); document.write( "The Pythagorean theorem says that the sum of the squares of the two legs of a right triangle \n" ); document.write( "is equal to the square of the hypotenuse of the triangle. In equation form this would be: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Where s represents the distance to the south of the starting point and e represents \n" ); document.write( "the distance to the east of the starting point. D is the distance between the two ships. \n" ); document.write( ". \n" ); document.write( "Substituting the two distances the ships have sailed at time t we get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Squaring the terms on the left side results in: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "You can then add the two terms on the left side: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Then to solve for D, take the square root of both sides: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "which reduces to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In this case we can ignore the negative solution because a negative distance between \n" ); document.write( "them really has no meaning. \n" ); document.write( ". \n" ); document.write( "So the distance between the two ships is 25 times the time in hours that the ships have \n" ); document.write( "been sailing. If they have been moving for 1 hour the distance between them is 25 miles. \n" ); document.write( "If they have been going for 2 hours, the distance between them is 25*2 = 50 miles. \n" ); document.write( "And so on ... \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem. \n" ); document.write( " |