document.write( "Question 74813This question is from textbook College Algebra
\n" ); document.write( ": Two ships leave port at the same time. One sails south at 15 mi/h and the other sails east at 20 mi/h. Find the function that models the distance (D) between the ships in terms of the time [(t) in hours] elapsed since their departure. \n" ); document.write( "
Algebra.Com's Answer #53751 by bucky(2189)\"\" \"About 
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This is a Pythagorean theorem problem. The two ships are at the vertex of a right angle.
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\n" ); document.write( "One ship sails east and the distance it is from the starting point is 20*t where t is the time
\n" ); document.write( "that it has been underway.
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\n" ); document.write( "The other ship sails south which is at an angle of 90 degrees to the path of the ship that
\n" ); document.write( "is going east. The distance that it is from the starting point is 15*t where t is also the
\n" ); document.write( "time that it has been underway.
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\n" ); document.write( "Both of these paths are the legs of a right triangle. The distance between the ships is
\n" ); document.write( "the hypotenuse of the triangle.
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\n" ); document.write( "The Pythagorean theorem says that the sum of the squares of the two legs of a right triangle
\n" ); document.write( "is equal to the square of the hypotenuse of the triangle. In equation form this would be:
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\n" ); document.write( "\"s%5E2+%2B+e%5E2+=+D%5E2\"
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\n" ); document.write( "Where s represents the distance to the south of the starting point and e represents
\n" ); document.write( "the distance to the east of the starting point. D is the distance between the two ships.
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\n" ); document.write( "Substituting the two distances the ships have sailed at time t we get:
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\n" ); document.write( "\"%2815t%29%5E2+%2B+%2820t%29%5E2+=+D%5E2\"
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\n" ); document.write( "Squaring the terms on the left side results in:
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\n" ); document.write( "\"225t%5E2+%2B+400t%5E2+=+D%5E2\"
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\n" ); document.write( "You can then add the two terms on the left side:
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\n" ); document.write( "\"625t%5E2+=+D%5E2\"
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\n" ); document.write( "Then to solve for D, take the square root of both sides:
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\n" ); document.write( "\"sqrt%28D%5E2%29+=+sqrt%28625t%5E2%29\"
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\n" ); document.write( "which reduces to:
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\n" ); document.write( "\"D+=+25t\" and \"D+=+-25t\"
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\n" ); document.write( "In this case we can ignore the negative solution because a negative distance between
\n" ); document.write( "them really has no meaning.
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\n" ); document.write( "So the distance between the two ships is 25 times the time in hours that the ships have
\n" ); document.write( "been sailing. If they have been moving for 1 hour the distance between them is 25 miles.
\n" ); document.write( "If they have been going for 2 hours, the distance between them is 25*2 = 50 miles.
\n" ); document.write( "And so on ...
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\n" ); document.write( "Hope this helps you to understand the problem.
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