document.write( "Question 888505: The hypotenuse of the right triangle is 26. One leg is 4 more than twice the other leg. Determine the length of the longer leg. \n" ); document.write( "
Algebra.Com's Answer #537487 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x = one of the legs. \n" ); document.write( "let y = the other leg. \n" ); document.write( "pythagorus says: \n" ); document.write( "x^2 + y^2 = 26^2 \n" ); document.write( "y = 2x + 4 \n" ); document.write( "x^2 + y^2 = 26^2 becomes: \n" ); document.write( "x^2 + (2x+4)^2 = 26^2 \n" ); document.write( "simplify to get: \n" ); document.write( "x^2 + 4x^2 + 16x + 16 = 676 \n" ); document.write( "combine like terms to get: \n" ); document.write( "5x^2 + 16x + 16 = 676 \n" ); document.write( "subtract 676 from both sides to get: \n" ); document.write( "5x^2 + 16x - 660 = 0 \n" ); document.write( "factor to get: \n" ); document.write( "(x-10)(5x+66) = 0 \n" ); document.write( "solve for x to get: \n" ); document.write( "x = 10 or x = -66/5 \n" ); document.write( "x can't be negative, so x = 10 \n" ); document.write( "if x = 10, then 2x+4 = 24 \n" ); document.write( "x = 10 \n" ); document.write( "y = 24 \n" ); document.write( "10^2 + 24^2 = 100 + 576 = 676 = 26^2 \n" ); document.write( "all is good. \n" ); document.write( "one leg is 10. \n" ); document.write( "the other leg is 24. \n" ); document.write( "the leg of 24 is 4 more than twice the leg of 10.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |