document.write( "Question 882579: Nondestructive evaluation is a method that is used to
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document.write( "describe the properties of components or materials without
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document.write( "causing any permanent physical change to the units. It includes
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document.write( "the determination of properties of materials and the
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document.write( "classification of flaws by size, shape, type, and location. This
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document.write( "method is most effective for detecting surface flaws and characterizing
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document.write( "surface properties of electrically conductive materials.
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document.write( "Data were collected that classified each component as
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document.write( "having a flaw or not, based on manual inspection and operator
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document.write( "judgment, and the data also reported the size of the crack
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document.write( "in the material. Do the components classified as unflawed
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document.write( "have a smaller mean crack size than components classified as
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document.write( "flawed? The results in terms of crack size (in inches) are
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document.write( "stored in . (Data extracted from B. D. Olin and W. Q.
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document.write( "Meeker, “Applications of Statistical Methods to Nondestructive
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document.write( "Evaluation,” Technometrics, 38, 1996, p. 101.)
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document.write( "a. Assuming that the population variances are equal, is
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document.write( "there evidence that the mean crack size is smaller for the
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document.write( "unflawed specimens than for the flawed specimens? (Use
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document.write( ")
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document.write( "b. Repeat (a), assuming that the population variances are
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document.write( "not equal.
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document.write( "c. Compare the results of (a) and (b).\r
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document.write( "
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document.write( "
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document.write( "Type Crack size
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document.write( "0 0.003
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document.write( "0 0.004
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document.write( "0 0.012
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document.write( "0 0.014
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document.write( "0 0.021
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document.write( "0 0.023
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document.write( "0 0.024
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document.write( "0 0.030
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document.write( "0 0.034
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document.write( "0 0.041
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document.write( "0 0.041
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document.write( "0 0.042
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document.write( "0 0.043
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document.write( "0 0.045
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document.write( "0 0.057
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document.write( "0 0.063
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document.write( "0 0.074
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document.write( "0 0.076
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document.write( "1 0.022
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document.write( "1 0.026
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document.write( "1 0.026
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document.write( "1 0.030
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document.write( "1 0.031
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document.write( "1 0.034
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document.write( "1 0.042
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document.write( "1 0.043
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document.write( "1 0.044
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document.write( "1 0.046
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document.write( "1 0.046
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document.write( "1 0.052
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document.write( "1 0.055
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document.write( "1 0.058
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document.write( "1 0.060
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document.write( "1 0.060
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document.write( "1 0.070
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document.write( "1 0.071
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document.write( "1 0.073
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document.write( "1 0.073
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document.write( "1 0.078
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document.write( "1 0.079
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document.write( "1 0.079
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document.write( "1 0.083
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document.write( "1 0.090
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document.write( "1 0.095
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document.write( "1 0.095
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document.write( "1 0.096
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document.write( "1 0.100
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document.write( "1 0.102
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document.write( "1 0.103
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document.write( "1 0.105
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document.write( "1 0.114
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document.write( "1 0.119
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document.write( "1 0.120
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document.write( "1 0.130
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document.write( "1 0.160
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document.write( "1 0.306
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document.write( "1 0.328
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document.write( "1 0.440
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document.write( "
Algebra.Com's Answer #537484 by lenjinx(1)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " |