document.write( "Question 888585: How many 5 letter code words can be formed using a 27 letter alphabet?
\n" ); document.write( "A-repetitions allowed
\n" ); document.write( "B-no repetitions allowed
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Algebra.Com's Answer #537475 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
if repetitions are allowed, then 27^5 = 14348907
\n" ); document.write( "if repetitions are not allowed, then 27P5 = 27! / 22! = 9687600\r
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\n" ); document.write( "\n" ); document.write( "how's this work?\r
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\n" ); document.write( "\n" ); document.write( "in order to see, try 2 letter code words from 3 letter alphabet of abc.\r
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\n" ); document.write( "\n" ); document.write( "with repetition = 3^2 = 9
\n" ); document.write( "without repetition = 3P2 = 3! / 1! = 6\r
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\n" ); document.write( "\n" ); document.write( "with repetition, the codes would be:\r
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\n" ); document.write( "\n" ); document.write( "aa
\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "ba
\n" ); document.write( "bb
\n" ); document.write( "ac
\n" ); document.write( "ca
\n" ); document.write( "cb
\n" ); document.write( "cc\r
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\n" ); document.write( "\n" ); document.write( "total of 9.\r
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\n" ); document.write( "\n" ); document.write( "without repetition, the codes would be:\r
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\n" ); document.write( "\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "ba
\n" ); document.write( "bc
\n" ); document.write( "ca
\n" ); document.write( "cb\r
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\n" ); document.write( "\n" ); document.write( "the same formulas apply to the bigger problem.\r
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\n" ); document.write( "\n" ); document.write( "the formula for permutation is nPx = n! / (n-x)!\r
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