document.write( "Question 888585: How many 5 letter code words can be formed using a 27 letter alphabet?
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document.write( "A-repetitions allowed
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document.write( "B-no repetitions allowed \n" );
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Algebra.Com's Answer #537475 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if repetitions are allowed, then 27^5 = 14348907 \n" ); document.write( "if repetitions are not allowed, then 27P5 = 27! / 22! = 9687600\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "how's this work?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in order to see, try 2 letter code words from 3 letter alphabet of abc.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with repetition = 3^2 = 9 \n" ); document.write( "without repetition = 3P2 = 3! / 1! = 6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "with repetition, the codes would be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "aa \n" ); document.write( "ab \n" ); document.write( "ac \n" ); document.write( "ba \n" ); document.write( "bb \n" ); document.write( "ac \n" ); document.write( "ca \n" ); document.write( "cb \n" ); document.write( "cc\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total of 9.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "without repetition, the codes would be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ab \n" ); document.write( "ac \n" ); document.write( "ba \n" ); document.write( "bc \n" ); document.write( "ca \n" ); document.write( "cb\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the same formulas apply to the bigger problem.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for permutation is nPx = n! / (n-x)!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |