document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888533>Question 888533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 96 and the length is 6 meters longer than twice the width. what are the length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537435 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39621)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter & rectangle dimensions questions like this are too typical.\r<BR>\n" );
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document.write( "L for length<BR>\n" );
document.write( "w for width\r<BR>\n" );
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document.write( "L=2w+6 and 2w+2L=96.  These are two equations in two unknowns, and easily solved.  \r<BR>\n" );
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document.write( "The perimeter equation in this example simplifies to w+L=48.  <BR>\n" );
document.write( "Substitute:  w+(2w+6)=48<BR>\n" );
document.write( "3w=48-6<BR>\n" );
document.write( "3w=42<BR>\n" );
document.write( "w=(6*7)/3<BR>\n" );
document.write( "w=14--------------one of the answers.\r<BR>\n" );
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document.write( "L=2*14+6 = ? </SPAN>\n" );
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