document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888480>Question 888480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Measure of a complementary angle is 30 degrees more than twice the given angle. Find measure of complementry angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537404 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set x = the measure of the angle.<BR>\n" );
document.write( "The complement of x is 90-x\r<BR>\n" );
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document.write( "complement = 30 plus twice the angle<BR>\n" );
document.write( "(90-x) = 30 + 2*x<BR>\n" );
document.write( "add x to each side<BR>\n" );
document.write( " 90 = 30 + 3x<BR>\n" );
document.write( "add -30 to each side<BR>\n" );
document.write( " 60 = 3x<BR>\n" );
document.write( "divide each side by 3<BR>\n" );
document.write( " 20 = x<BR>\n" );
document.write( "Since the complement of x = (90-x)<BR>\n" );
document.write( "The complement is 90-x = 90-20 = 70\r<BR>\n" );
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