document.write( "Question 888414: How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
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Algebra.Com's Answer #537371 by lwsshak3(11628)\"\" \"About 
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How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to obtain 40 liters of 8% alcohol solution?
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\n" ); document.write( "let x=amt of 10% solution to mix
\n" ); document.write( "40-x=amt of 5% solution to mix
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\n" ); document.write( "10%x+5%(40-x)=8%*40
\n" ); document.write( ".10x++2-.05x=3.2
\n" ); document.write( ".05x=1.2
\n" ); document.write( "x=24
\n" ); document.write( "40-x=16
\n" ); document.write( "amt of 10% solution to mix=24 liters
\n" ); document.write( "amt of 5% solution to mix=16 liters
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