document.write( "Question 888287: average price of 12 goats and 12 sheeps is is Rs.600.if price of sheep is twice of a
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document.write( " goat find total price of 3 goats and 2 sheep
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document.write( "2)average price monthly salary of A,B.Cis 600 and that ofB,C,Dis Rs 750.if D salary is Rs 900 a month find A monthly salary.
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document.write( "3)miandad scored 85 runs in 17th inning and increased run average of previous 16 inning by 3.what were his average runs in 17 inning \n" );
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Algebra.Com's Answer #537363 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! In the future, please list these as separate problems. They'll get answered a lot more quickly. Thank you.\r \n" ); document.write( "\n" ); document.write( "1) 12G + 12S = 24*600 \n" ); document.write( "12G + 12S = 14400 \n" ); document.write( "S = 2G \n" ); document.write( "Substitute the value of S into the top equation \n" ); document.write( "12G + 12(2G) = 14400 \n" ); document.write( "12G + 24G = 14400 \n" ); document.write( "36G = 14400 \n" ); document.write( "Divide each side by 36 \n" ); document.write( "G = 400 \n" ); document.write( "If a goat costs 400, then a sheep costs 800 \n" ); document.write( "Price for 3 goats and 2 sheep = 3(400) + 2(800), or 1200+1600, or 2800\r \n" ); document.write( "\n" ); document.write( "2) A + B + C = 600*3, or 1800 \n" ); document.write( "B + C + D = 750*3, or 2250 \n" ); document.write( "D = 900 \n" ); document.write( "Therefore, B + C = 2250-900, or 1350 \n" ); document.write( "Since A + B + C = 1800, subtract B+c (1350) to get A = 450\r \n" ); document.write( "\n" ); document.write( "3) 34 \n" ); document.write( " \n" ); document.write( " |