document.write( "Question 888401: The sum of A and B is 35. Ten years ago A was double B's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #537361 by JulietG(1812)\"\" \"About 
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A + B = 35, which means that A = 35-B
\n" ); document.write( "(A-10) = 2(B-10)
\n" ); document.write( "Distribute
\n" ); document.write( "A-10 = 2B-20
\n" ); document.write( "Substitute the value of A from the first equation
\n" ); document.write( "(35-B)-10 = 2B-20
\n" ); document.write( "25-B = 2B - 20
\n" ); document.write( "Add 20 to each side
\n" ); document.write( "45 - B = 2B
\n" ); document.write( "Add B to each side
\n" ); document.write( "45 = 3B
\n" ); document.write( "Divide each side by 3
\n" ); document.write( "15 = B
\n" ); document.write( "If B is 15, then A must be 20.
\n" ); document.write( ".
\n" ); document.write( "Let's check...
\n" ); document.write( "Ten years ago, A would have been 10 and B would have been 5 -- 10 is double 5.
\n" ); document.write( "Success!
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