document.write( "Question 888401: The sum of A and B is 35. Ten years ago A was double B's age. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #537361 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! A + B = 35, which means that A = 35-B \n" ); document.write( "(A-10) = 2(B-10) \n" ); document.write( "Distribute \n" ); document.write( "A-10 = 2B-20 \n" ); document.write( "Substitute the value of A from the first equation \n" ); document.write( "(35-B)-10 = 2B-20 \n" ); document.write( "25-B = 2B - 20 \n" ); document.write( "Add 20 to each side \n" ); document.write( "45 - B = 2B \n" ); document.write( "Add B to each side \n" ); document.write( "45 = 3B \n" ); document.write( "Divide each side by 3 \n" ); document.write( "15 = B \n" ); document.write( "If B is 15, then A must be 20. \n" ); document.write( ". \n" ); document.write( "Let's check... \n" ); document.write( "Ten years ago, A would have been 10 and B would have been 5 -- 10 is double 5. \n" ); document.write( "Success! \n" ); document.write( " \n" ); document.write( " |