document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888420>Question 888420</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a circle has a radius length of 2x units, what is the circle’s circumference?\r<BR>\n" );
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document.write( "The choices are:<BR>\n" );
document.write( "1) pi(x)<BR>\n" );
document.write( "2) 1/2 pi(x)<BR>\n" );
document.write( "3) 4 pi(x)<BR>\n" );
document.write( "4) 2 pi(x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537355 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The formula for circumference of a circle is C=Pi*Diameter (or 2 Pi R)<BR>\n" );
document.write( "If the radius is 2x, simply insert that value into the formula to get<BR>\n" );
document.write( "C = 2 Pi (2X) or C = 4 Pi X </SPAN>\n" );
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