document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=888310>Question 888310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need the answer to the following problem, if possible show work so that I can see how to work it out.\r<BR>\n" );
document.write( "\n" );
document.write( "Let a random sample be taken of size n=36 from a population with known standard deviation of &#963; = 3.  Suppose that the mean of the sample is x&#773; = 37.  The approximate 95% confidence interval for the mean, &#956;, of the population from which the sample was drawn is: </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #537309 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=537309\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> alpha = 1-0.95 = 0.05\r<BR>\n" );
document.write( "\n" );
document.write( "z(alpha/2) = z0.025 = 1.96\r<BR>\n" );
document.write( "\n" );
document.write( "CI (Lower,UPPer)\r<BR>\n" );
document.write( "\n" );
document.write( "Lower = x-bar - z0.025(&#963;)/sqrt(n)  = 37 - 1.96(3)/6 = 36.02\r<BR>\n" );
document.write( "\n" );
document.write( "Lower = x-bar + z0.025(&#963;)/sqrt(n)  = 37 + 1.96(3)/6 = 37.98\r<BR>\n" );
document.write( "\n" );
document.write( "Answer: (36.02,37.98)\r<BR>\n" );
document.write( "\n" );
document.write( "If you need more help you can contact me at:\r<BR>\n" );
document.write( "\n" );
document.write( "mthman@gmail.com\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );