document.write( "Question 888312: A cruise ship left the Bahamas two hours before a speedboat. The boats traveled in opposite directions. The speedboat traveled at 25 mph for two hours. After this amount of time, the vessels were 90 miles apart. Find the cruise ship's speed.
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Algebra.Com's Answer #537305 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I call this a \" head start \" problem. The cruise
\n" ); document.write( "ship has a \"+2+\" hr head start.
\n" ); document.write( "Let \"+d%5B1%5D+\" = the cruse ship's head start
\n" ); document.write( "in miles.
\n" ); document.write( "Let \"+s+\" = the cruise ship's speed in miles / hr
\n" ); document.write( "(1) \"+d%5B1%5D+=+2s+\"
\n" ); document.write( "This is the head start
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\n" ); document.write( "After 2 hrs, the speedboat has traveled
\n" ); document.write( "\"+d%5B2%5D+=+25%2A2+\"
\n" ); document.write( "\"+d%5B2%5D+=+50+\" mi
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\n" ); document.write( "The vessels are \"+90+\" mi apart after \"+2+\" hrs
\n" ); document.write( "The cruise ship has traveled \"+2s+\" again in the \"+2+\" hrs
\n" ); document.write( "since the speedboat left
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\n" ); document.write( "\"+2s+%2B+2s+%2B+50+=+90+\"
\n" ); document.write( "\"+4s+=+90+-+50+\"
\n" ); document.write( "\"+4s+=+40+\"
\n" ); document.write( "\"+s+=+10+\"
\n" ); document.write( "The cruise ship's speed is 10 mi/hr
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\n" ); document.write( "This makes sense because in \"+4+\" hrs the cruise ship
\n" ); document.write( "traveled \"+90+-+50+=+40+\" mi
\n" ); document.write( "\"+40%2F4+=+10+\" mi/hr
\n" ); document.write( "Hope this helps\r
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