document.write( "Question 888311: The sum of the digits of a two digit number is 5.
\n" ); document.write( "On reversing the digits of the number, the octane
\n" ); document.write( "number exceeds the original number by 9. Find the
\n" ); document.write( "original number.
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Algebra.Com's Answer #537268 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let \"x\" be the tens digit
\n" ); document.write( "let \"y\" be the units/ones digit \r
\n" ); document.write( "\n" ); document.write( "the sum of the digits of a two digit number is \"5\", so we \r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+5\" \r
\n" ); document.write( "\n" ); document.write( "when the digits are reversed, the number is \"9\" more than the original \r
\n" ); document.write( "\n" ); document.write( "since \"x\" is your tens digit, its value is \"10x\" \r
\n" ); document.write( "\n" ); document.write( "so you have the value of your original number \"10x+%2B+y\" \r
\n" ); document.write( "\n" ); document.write( "when you reversed it, the new number is \"10y+%2B+x\"} \r
\n" ); document.write( "\n" ); document.write( "we have \"10y+%2B+x+=+9+%2B+10x+%2B+y+\"}\r
\n" ); document.write( "\n" ); document.write( "manipulate the equation above this sentence: \r
\n" ); document.write( "\n" ); document.write( "\"9y+-+9x+=+9\"} or \r
\n" ); document.write( "\n" ); document.write( "\"y+-+x+=+1\" \r
\n" ); document.write( "\n" ); document.write( "solve \"x\" and \"y\" with the equation from the top, which is \"x+%2B+y+=+5\" \r
\n" ); document.write( "\n" ); document.write( "\"y+-+x+=+1\"
\n" ); document.write( "\"x+%2B+y+=+5\"
\n" ); document.write( "_____________________add both and we get \r
\n" ); document.write( "\n" ); document.write( "\"2y+=+6\" after adding two equations, then \r
\n" ); document.write( "\n" ); document.write( "\"highlight%28y+=+3%29\" \r
\n" ); document.write( "\n" ); document.write( "to solve for \"x\", plug solution for \"y\" in one of the equations above \r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+y+=+5\"
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\n" ); document.write( "\"x+%2B+3=+5+\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x+=+2+%29\"\r
\n" ); document.write( "\n" ); document.write( "hence the number is \"highlight%2823%29\"\r
\n" ); document.write( "\n" ); document.write( " if the digits are reversed, the number is \"32\" which is \"9\" more than the number \"23\"\r
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