document.write( "Question 888311: The sum of the digits of a two digit number is 5.
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document.write( "On reversing the digits of the number, the octane
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document.write( "number exceeds the original number by 9. Find the
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document.write( "original number. \n" );
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Algebra.Com's Answer #537268 by MathLover1(20850) You can put this solution on YOUR website! \n" ); document.write( "let \n" ); document.write( "let \n" ); document.write( "\n" ); document.write( "the sum of the digits of a two digit number is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when the digits are reversed, the number is \n" ); document.write( "\n" ); document.write( "since \n" ); document.write( "\n" ); document.write( "so you have the value of your original number \n" ); document.write( "\n" ); document.write( "when you reversed it, the new number is \n" ); document.write( "\n" ); document.write( "we have \n" ); document.write( "\n" ); document.write( "manipulate the equation above this sentence: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "_____________________add both and we get \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to solve for \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hence the number is \n" ); document.write( "\n" ); document.write( " if the digits are reversed, the number is \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |