document.write( "Question 888276: If f(x) = √x^2-1 and g(x) = √x-1 which expression represents f(x)/g(x) for x>1? \n" ); document.write( "
Algebra.Com's Answer #537265 by Theo(13342)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "following is the graph of the equation of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "following is the graph of the equation of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first graph doesn't allow values of x = 1 because that would make the denominator equal to 0 and the function would be undefined.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the first graph also doesn't allow values of x <1 because that would make the numerator the squart root of a negative number which is also undefined in the real number system.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the second graph goes to 0 because x+1 will be positive for values less than 1 of x but greater than or equal to 0 and will also allows x = 1 because there is no denominator in that equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the 2 equations are equivalent except that once you eliminated the denominator by canceling it out, you can then get a defined solution at x = 1.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |