document.write( "Question 888254: How do you factor x^4 +x^2*y^2+y^4 into (x^2+xy+y^2)(x^2-xy+y^2)? Thank you.
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Algebra.Com's Answer #537260 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"x%5E4+%2Bx%5E2y%5E2%2By%5E4\"\r\n" );
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document.write( "We recognize that if there were a 2 coefficient on the\r\n" );
document.write( "middle term, the expression with be a perfect square\r\n" );
document.write( "trinomial.  We can make it have a coefficient of 2 by\r\n" );
document.write( "adding \"x%5E2y%5E2\".  But if we do that we'll have to also\r\n" );
document.write( "subtract \"x%5E2y%5E2\" to offset.\r\n" );
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document.write( "But that's OK for then we'll have the difference of \r\n" );
document.write( "two squares, and we know how to factor that.\r\n" );
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document.write( "So we add \"x%5E2y%5E2\" to the middle term to make it \r\n" );
document.write( "\"2x%5E2y%5E2\" and then subtract \"x%5E2y%5E2\":\r\n" );
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document.write( "\"x%5E4%2B2x%5E2y%5E2%2By%5E4-x%5E2y%5E2\"\r\n" );
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document.write( "\"%28x%5E4%2B2x%5E2y%5E2%2By%5E4%29-x%5E2y%5E2\"\r\n" );
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document.write( "factor the first term as a perfect square and write the\r\n" );
document.write( "second term as a square\r\n" );
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document.write( "\"%28x%5E2%2By%5E2%29%5E2-%28xy%29%5E2\"\r\n" );
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document.write( "which is the difference of two squares, and factors\r\n" );
document.write( "like \"A%5E2-B%5E2=%28A-B%29%28A%2BB%29\" with \"A=%28x%5E2%2By%5E2%29\" and \"B=xy\":\r\n" );
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document.write( "\"%28%28x%5E2%2By%5E2%29-xy%29%28%28x%5E2%2By%5E2%29%2Bxy%29\"\r\n" );
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document.write( "Remove the inner parentheses:\r\n" );
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document.write( "\"%28x%5E2%2By%5E2-xy%29%28x%5E2%2By%5E2%2Bxy%29\"\r\n" );
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document.write( "Write in descending order of x and ascending order of y:\r\n" );
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document.write( "\"%28x%5E2-xy%2By%5E2%29%28x%5E2%2Bxy%2By%5E2%29\"\r\n" );
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document.write( "Edwin
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